| 尝试为将跟踪每日视图的表插入初始行时,出现错误: 
Fatal error: Call to a member function bind_param() on a non-object in /…/functions.php on line 157 该行是以下组的最后一行: if($stats_found) {
 $sqlquery = "UPDATE vid_stats SET views = ? WHERE title = ? AND format = ? AND date = ? AND results = ?";
 $views++;
} else {
 $sqlquery = "INSERT INTO vid_stats (views,title,format,results) values (?,?,? )";
 $views = 1;
}
$stmt = $mysqli->prepare($sqlquery);
/* bind parameters for markers */
$stmt->bind_param("dsss",$views,$title,$format,"success");
 关于这个问题有什么暗示吗? 以防万一周围的代码有问题,这是完整的功能: 最佳答案
问题是用户错误:我的结果列名称错误.function updateViewCount($title,$results) {
 //update view count
 global $mysqli;
 $views = 0;
 if ($stmt = $mysqli->prepare("SELECT views FROM vid_stats WHERE title = ? AND format = ? AND date = ?")) {
  /* bind parameters for markers */
  $stmt->bind_param("ssd",date("Y-m-d"));
  /* execute query */
  $stmt->execute();
  /* bind result variables */
  $stmt->bind_result($views);
  /* fetch value */
  if ($stmt->fetch()) {
   $stats_found = true;
  } else { $stats_found = false; }
  /* close statement */
  $stmt->close();
  if($stats_found) {
   $sqlquery = "UPDATE vid_stats SET views = ? WHERE title = ? AND format = ? AND date = ? AND results = ?";
   $views++;
  } else {
   $sqlquery = "INSERT INTO vid_stats (views,? )";
   $views = 1;
  }
  $stmt = $mysqli->prepare($sqlquery);
  /* bind parameters for markers */
  echo $sqlquery."<br>".$views."<br>".$title."<br>".$format;
  $stmt->bind_param("dsss","success");
  /* execute query */
  $stmt->execute();
  /* close statement */
  $stmt->close();
 }
}
 当我添加echo $mysqli-> error时,发现了这一点;在$stmt = $mysqli-> prepare($sqlquery)行之后;揭示了列名错误. (编辑:鹰潭站长网) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |