sql – MS ACCESS：如何使用访问查询计算不同的值？

这是下面给出的当前复杂查询.

SELECT DISTINCT Evaluation.ETCode,Training.TTitle,Training.Tcomponent,Training.TImpliment_Partner,Training.TVenue,Training.TStartDate,Training.TEndDate,Evaluation.EDate,Answer.QCode,Answer.Answer,Count(Answer.Answer) AS [Count],Questions.SL,Questions.Question
FROM ((Evaluation INNER JOIN Training ON Evaluation.ETCode=Training.TCode) INNER JOIN Answer ON Evaluation.ECode=Answer.ECode) INNER JOIN Questions ON Answer.QCode=Questions.QCode
GROUP BY Evaluation.ETCode,Training.Tvenue,Questions.Question,Questions.SL
ORDER BY Answer.QCode,Answer.Answer;

另一栏是Training.TCode.我需要计算明显的Training.TCode,有人可以帮帮我吗？
如果您需要更多信息,请告诉我

解决方法

select ...,count(distinct Training.Tcode) as ...,...

编辑 – 请现在看看这个……

采用以下SQL代码.第一个选择是SQL服务器如何执行此操作,第二个查询应该是访问兼容…

declare @t table (eCode int,tcode int)
insert into @t values(1,1)
insert into @t values(1,2)
insert into @t values(1,3)
insert into @t values(2,2)
insert into @t values(2,3)
insert into @t values(3,1)    

select 
    ecode,count(distinct tCode) countof
from
    @t
group by
    ecode

select ecode,count(*)
from
    (select distinct tcode,ecode
    from  @t group by tcode,ecode) t
group by ecode

它返回以下内容：

ecode tcode
1       3 (there are 3 distinct tcode for ecode of 1)
2       2 (there are 2 distinct tcode for ecode of 2)
3       1 (there is 1 distinct tcode for ecode of 3)

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